# Thread: Formula for the n-th term . Sequence Question

1. ## Formula for the n-th term . Sequence Question

Hi, I am new to this forum and I am also very new to math. I failed math in high school so my understanding of algebra is very weak. Even so, I would like to learn so please bare with me if I am being a nuisance.

Question

Find formula, showing all the work for the n-th term tn of the sequence (tn) . Defined with

t1 = 8; tn = ( 5*tn-1 ): 2; *tn-1 = previous term

I understand a little bit of this

GCSE Maths Sequences Revision - The nth Term | S-cool, the revision website

however, I can't seems to relate this with the question I am facing.

Any help is appreciated

2. ## Re: Formula for the n-th term . Sequence Question

Each term is 5 times higher than the previous term, sequences like these are called geometric sequences, since the first term is 8 and the common ratio is 5 the formula for the nth term is 8*5n-1

3. ## Re: Formula for the n-th term . Sequence Question

Thanks a lot dude! that explains a lot

4. ## Re: Formula for the n-th term . Sequence Question

Sorry actually I am a bit lost

If t1 = 8; and tn = (5*tn-1) /2
Then t3 = (5*20)/2 = 50

But using the n-th term mentioned wont it be
t(3) = 8*5^n-1
= 8*5^2
= 8*25
= 400

I am very new to this, so I'm sorry if i misunderstood you somewhere

5. ## Re: Formula for the n-th term . Sequence Question

Originally Posted by RedGuitar
Sorry actually I am a bit lost
If t1 = 8; and tn = (5*tn-1) /2
Then t3 = (5*20)/2 = 50
But using the n-th term mentioned wont it be
t(3) = 8*5^n-1
= 8*5^2
= 8*25
= 400
I am very new to this, so I'm sorry if i misunderstood you somewhere

Your confusion results from your inability to post clearly what you mean.

Is it now $t_1=8~\&~t_{n}=\left(\frac{5}{2}\right)t_{n-1}~?$

6. ## Re: Formula for the n-th term . Sequence Question

The formula given is

7. ## Re: Formula for the n-th term . Sequence Question

Originally Posted by RedGuitar
The formula given is

Why don't you see that $\left( {\frac{{5{t_{n - 1}}}}{2}} \right) = \left( {\frac{5}{2}} \right){t_{n - 1}}~?$

8. ## Re: Formula for the n-th term . Sequence Question

Oh I see it now,

How does sequence is normally solved? Do we eye ball for a pattern or is there a magic formula for it?

Plato can you please show me step by step to find the n term, please? I've been stuck with this for hours : (.

I tried to follow this Geometric Sequences and Series but I am still confused.

9. ## Re: Formula for the n-th term . Sequence Question

Originally Posted by RedGuitar
How does sequence is normally solved? Do we eye ball for a pattern or is there a magic formula for it?
${t_n} = 8 \cdot {\left( {\frac{5}{2}} \right)^{n - 1}}$

10. ## Re: Formula for the n-th term . Sequence Question

Thanks a lot, I assume nth term = dn + (a - d) comes in play?

Thank you for your time everyone, it's been a great help

11. ## Re: Formula for the n-th term . Sequence Question

Originally Posted by RedGuitar
Thanks a lot, I assume nth term = dn + (a - d) comes in play?

Thank you for your time everyone, it's been a great help
That is for an arithmetic sequence, this is a geometric sequence.