A cubic function f is defined for x ∈ R as f (x) = x^{3}+ (1 - k^{2})x + k, where k is a constant. Show that -k is a root of f. How would I go about doing this? Help appreciated!
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Originally Posted by HelenMc9 A cubic function f is defined for x ∈ R as f (x) = x^{3}+ (1 - k^{2})x + k, where k is a constant. Show that -k is a root of f. How would I go about doing this? Help appreciated! What is
Aah yes it's equal to zero because -k is a root... I know what to do now! thanks!!
By the way, "root" is the wrong word here. You can find a "root" of an equation such as f(x)= 0, or a "zero" of a function, that being, of course, the root of the equation f(x)= 0.
Originally Posted by HallsofIvy By the way, "root" is the wrong word here. . There does seem to be general agreement on that. See zero here and root there.
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