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Thread: Why do graphs such y = (1/4)^x + 4 still have values for 4?

  1. March 8th 2013, 02:52 AM #1
    iamapineapple
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    Why do graphs such y = (1/4)^x + 4 still have values for 4?

    Because y = 4 is the asymptote?
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  2. March 8th 2013, 04:22 AM #2
    HallsofIvy
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    Re: Why do graphs such y = (1/4)^x + 4 still have values for 4?

    I have no clue what you mean by this. What do you mean by "values for 4"? My first thought was that "for 4" meant "for x= 4" but that's easy to calculate- if x= 4, then y= (1/4)^4+ 4= \frac{1}{64}+ \frac{256}{64}= \frac{257}{64}. If you mean "there exist x such that y= 4", it is not true. If (1/4)^x+ 4= 4, then (1/4)^x= 0 and there is no such x.
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