hi, Im a bit puzzled on a question and answer I have 5-ax=b and I have to make x the subject. The given answer is x=5-b/a but Im not getting how this is achived Dave
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$\displaystyle \displaystyle \begin{align*} 5 - a\,x &= b \\ -a\,x &= b - 5 \\ a\,x &= 5 - b \\ x &= \frac{5 - b}{a} \end{align*}$
thanks, just two questions from -ax=b-5 why does the a lose its - and why is b-5 switched around? Dave
Originally Posted by davellew69 thanks, just two questions from -ax=b-5 why does the a lose its - and why is b-5 switched around? Dave Multiply both sides by -1, then distribute.
can you explain why you multiply both side by -1 and what is meant by distriute? by multiplying both side by -1 would that not make b+5 dave
Last edited by davellew69; Mar 7th 2013 at 01:37 AM.
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