hi, Im a bit puzzled on a question and answer

I have 5-ax=b and I have to make x the subject. The given answer is x=5-b/a but Im not getting how this is achived

Dave

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- Mar 7th 2013, 01:16 AMdavellew69changing the subject of a formula
hi, Im a bit puzzled on a question and answer

I have 5-ax=b and I have to make x the subject. The given answer is x=5-b/a but Im not getting how this is achived

Dave - Mar 7th 2013, 01:19 AMProve ItRe: changing the subject of a formula
$\displaystyle \displaystyle \begin{align*} 5 - a\,x &= b \\ -a\,x &= b - 5 \\ a\,x &= 5 - b \\ x &= \frac{5 - b}{a} \end{align*}$

- Mar 7th 2013, 01:23 AMdavellew69Re: changing the subject of a formula
thanks, just two questions from -ax=b-5 why does the a lose its - and why is b-5 switched around?

Dave - Mar 7th 2013, 01:24 AMProve ItRe: changing the subject of a formula
- Mar 7th 2013, 01:27 AMdavellew69Re: changing the subject of a formula
can you explain why you multiply both side by -1 and what is meant by distriute? by multiplying both side by -1 would that not make b+5

dave