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Math Help - its me again -.- help with another exponential question? :D

  1. #1
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    Lightbulb its me again -.- help with another exponential question? :D

    Solve the following equation:





    Answer:

    I don't know what to do with the 15!!!
    Help me? Pretty pleaseeee?

    Thank you very much!!
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  2. #2
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    Re: its me again -.- help with another exponential question? :D

    Hey pumbaa213.

    Apart from trial and error, you will probably have to use a root finding algorithm. Have you come across this in class?
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    Re: its me again -.- help with another exponential question? :D

    its me again -.- help with another exponential question? :D-exponantial-q.png
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    Senior Member Paze's Avatar
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    Re: its me again -.- help with another exponential question? :D

    Quote Originally Posted by ibdutt View Post
    Click image for larger version. 

Name:	Exponantial Q.png 
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    Do you solve the last part with logarithms or have they not been taught when solving these? I just want to make sure I am not using anything that is ''not allowed''.
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  5. #5
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    Re: its me again -.- help with another exponential question? :D

    You don't need logarithms. It should be obvious that if 2^x= 2 then x= 1. (You do need to know that y= a^x, for a positive, is a "one-to-one function" to know that x= 1 is the only solution.
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    Senior Member Paze's Avatar
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    Re: its me again -.- help with another exponential question? :D

    Quote Originally Posted by HallsofIvy View Post
    You don't need logarithms. It should be obvious that if 2^x= 2 then x= 1. (You do need to know that y= a^x, for a positive, is a "one-to-one function" to know that x= 1 is the only solution.
    Okay, so we don't need logarithm until the answer becomes more complicated..Like x=2/3 or something. Right?
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    Re: its me again -.- help with another exponential question? :D

    X is not equal to 1
    2^4 is not equal to 0+15
    If X = 0.9999 you get a close equality
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