# Double check my answers? Thank you!~

• Mar 2nd 2013, 07:38 PM
pumbaa213
Double check my answers? Thank you!~
• Mar 2nd 2013, 07:41 PM
pumbaa213
Re: Double check my answers? Thank you!~
But the answer at the back is 7. If my answer is wrong how do i solve it then? thanks a lot!
• Mar 2nd 2013, 08:04 PM
sakonpure6
Re: Double check my answers? Thank you!~
in a case like this, just sub in the value of x and solve both sides and see if they are equal.
• Mar 2nd 2013, 08:20 PM
Cesc1
Re: Double check my answers? Thank you!~
Quote:

Originally Posted by pumbaa213

$12^x$ is not the same as $4*3^x$

You should solve it like this:

$12^x=(3^x)(2^{x+7})$

But $2^{x+7}=(2^x)(2^7)$

So you have

$12^x=(3^x)(2^x)(2^7)=(6^x)(2^7)$

Can you solve that?

Let us know if you need more help!
• Mar 2nd 2013, 08:30 PM
pumbaa213
Re: Double check my answers? Thank you!~
Thank you sakonpure6 and Cesc1 for your guys help!:) I think i'll still need more assistance on how to solve the question. I've tried but im still not sure what to do after this step.

12^x=(6^x)(2^7)

How should i split 12^x to get a 6 and 2? Thank you!!
• Mar 2nd 2013, 08:36 PM
Cesc1
Re: Double check my answers? Thank you!~
Quote:

Originally Posted by pumbaa213
Thank you sakonpure6 and Cesc1 for your guys help!:) I think i'll still need more assistance on how to solve the question. I've tried but im still not sure what to do after this step.

12^x=(6^x)(2^7)

How should i split 12^x to get a 6 and 2? Thank you!!

$12^x=(6^x)(2^7)$

But $12^x=(6*2)^x=(6^x)(2^x)$

So $(6^x)(2^x)=(6^x)(2^7)$

Divide both sides by $6^x$ and you get

$2^x=2^7$

So $x=7$
• Mar 2nd 2013, 08:40 PM
pumbaa213
Re: Double check my answers? Thank you!~
Thanks for the reply. But mind if i ask, wont (6^x) x (2^x) give you 12^x^2?
Sorry if im wrong. I had a huge break from math! ><
• Mar 2nd 2013, 08:54 PM
pumbaa213
Re: Double check my answers? Thank you!~
WAIT! I get it!! ^V^
THANKS EVERYBODY! YOU'VE bEEN OF GREAT HELP! <3