Re: Algebra (Volume, Ratios)

Well start by setting two of the volumes equal to each other.

$\displaystyle \displaystyle \begin{align*} \frac{1}{3}\,\pi\, t^2 \, w &= \pi \, t^2 \, s \end{align*}$

and find the relationship between w and s. You should be able to form the ratio between them from there.

Re: Algebra (Volume, Ratios)

So I did (1/3)πt^{2}w = πt^{2}s and came out with s = (1/3)w and thus w = s/(1/3). I tried solving (1/3)πt^{2}w = (1/2)*(4/3)πt^{3} for t but failed miserably.

Have I done this right? Also, what significance does this have in finding the ratio?

Re: Algebra (Volume, Ratios)

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Re: Algebra (Volume, Ratios)

Re: Algebra (Volume, Ratios)

Quote:

Originally Posted by

**ibdutt**

So how did you go from having *(1/3)w = s = (2/3)t* to having the ratio (6:2:3)?

And also, where did "k" come from?

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Re: Algebra (Volume, Ratios)

Re: Algebra (Volume, Ratios)

Thanks heaps. One final question to clarify my understanding: do we divide by 2 to make each fraction (1/X), (1/Y), etc? (i.e to turn (2/3) into (1/3) we must divide it by 2 and thus all the others by 2)

Re: Algebra (Volume, Ratios)

Yes we divide the fractions by a suitable number so that we have 1 in the numerator of each fraction, in this case we divide by 2.

Re: Algebra (Volume, Ratios)