Hi I have to solve a really hard simultaneous equation and I don't know how to do it.

Please note it has p1,p2,p3,q1,q2,q3. The numbers are subscripts.
These all represent constant values. That is they are not variables.
The two variables are x and y.

1. x(q2+q3-2q1)-y(p2+p3-2p1)+(q1p2-p1q2)+(q1p3-q3p1)=0
2. x(2q2-q1-q3)-y(2p2-p1-p3)+(p2q1-q2p1)+(p2q3-q2p3)=0

I have tried to solve this by re-arranging then subbing in but this quickly gets out of hand as the subbed in equation is very long and

Originally Posted by James7361539
Hi I have to solve a really hard simultaneous equation and I don't know how to do it.

Please note it has p1,p2,p3,q1,q2,q3. The numbers are subscripts.
These all represent constant values. That is they are not variables.
The two variables are x and y.

1. x(q2+q3-2q1)-y(p2+p3-2p1)+(q1p2-p1q2)+(q1p3-q3p1)
2. x(2q2-q1-q3)-y(2p2-p1-p3)+(p2q1-q2p1)+(p2q3-q2p3)

I have tried to solve this by re-arranging then subbing in but this quickly gets out of hand as the subbed in equation is very long and

Those aren't equations.

Originally Posted by a tutor
Those aren't equations.
Sorry I forgot the =0 at the end of them
I have edited my post now.

So, essentially, you have Ax+ By= C and Dx+ Ey= F. Multiply the first equation by E, the second equation by B, and subtract:
(AE- BD)x= CE- BF, x= (CE- BF)/(AE- BD).

Multiply the first equation by D, the second equation by A, and subtract:
(BD- AE)y= CD- AF, x= (CD- AF)/(BD- AE).

Now replace A, B, C, D, E, and F with those complicated expressions.