# Simplifying algebraic expressions

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• Feb 26th 2013, 12:56 PM
mrmorrison
Simplifying algebraic expressions
Hi,

This is quite a basic query but I am having difficulty figuring out the following and would like some assistance.

(x+3)-(x+1)

= x+3-x-1

=2

I don't understand how we end up with = x+3-x-1

Could some please explain the steps taken to get here?

Many thanks
• Feb 26th 2013, 01:17 PM
HallsofIvy
Re: Simplifying algebraic expressions
Quote:

Originally Posted by mrmorrison
Hi,

This is quite a basic query but I am having difficulty figuring out the following and would like some assistance.

(x+3)-(x+1)

= x+3-x-1

=2

I don't understand how we end up with = x+3-x-1

It's the "distributive law": a(b+ c)= ab+ ac. Here -1(x+ 1)= (-1)x+ (-1)(1)= -x- 1.

Quote:

Could some please explain the steps taken to get here?

Many thanks
• Mar 9th 2013, 03:55 AM
mrmorrison
Re: Simplifying algebraic expressions
Thanks for your help, this had made it much clearer!
• Mar 9th 2013, 12:48 PM
fanna1119
Re: Simplifying algebraic expressions
I use to get so confused with expressions like this but its pretty simple actually :)
if you see -+ sign in between the two you should know you have to multiply them with the numbers inside the brackets.
(x+3) -(x+1)
(x+3) -1(x+1) there is a imaginary 1 after the negative value if you can see it like that.
x+3 -x-1
x+3-x-1
x-x=0
3-1=2
:)