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Math Help - Expanding and Expanding brackets with FRACTIONAL POWERS

  1. #1
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    Expanding and Expanding brackets with FRACTIONAL POWERS

    Hey guys,
    bit stuck on how to expand+simply this equation. could you please help me out and post how to do get to the simplified equation?

    the equation being: Expanding and Expanding brackets with FRACTIONAL POWERS-capture.jpg

    thanks in advance.
    Gamei
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  2. #2
    Senior Member MacstersUndead's Avatar
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    Re: Expanding and Expanding brackets with FRACTIONAL POWERS

    You use the foil method as you would when multiplying polynomials of integer exponents. for a pair of binomials the foil method is (a+b)(c+d) = a(c+d) + b(c+d) = ac + ad + bc + bd (rearranging for like terms afterward)

    so in this case we have
    (2x^\frac{1}{2}-3y^\frac{3}{2})(2x^\frac{1}{2} + 3y^\frac{3}{2})
    (2x^\frac{1}{2})(2x^\frac{1}{2}) + (2x^\frac{1}{2})(3y^\frac{3}{2}) - (2x^\frac{1}{2})(3y^\frac{3}{2}) - (3y^\frac{3}{2})(3y^\frac{3}{2})
    (2x^\frac{1}{2})(2x^\frac{1}{2}) - (3y^\frac{3}{2})(3y^\frac{3}{2})
    4x - 9y^3 by exponent rules. Recall (a^b)(a^c) = a^{b+c}
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    Re: Expanding and Expanding brackets with FRACTIONAL POWERS

    Quote Originally Posted by gamei View Post
    Hey guys,
    bit stuck on how to expand+simply this equation. could you please help me out and post how to do get to the simplified equation?
    the equation being: Click image for larger version. 

Name:	Capture.JPG 
Views:	1 
Size:	12.4 KB 
ID:	27204

    Oh come on, the sum and difference of squares: 2x-9y^3
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