Let x = her present age.

So, x -6 = her age six years ago

And, x +6 = her age in six years time

(x-6)^2 = x +6

x^2 -12x +36 = x +6

x^2 -12x -x +36 -6 = 0

x^2 -13x +30 = 0

(x -10)(x -3) = 0

x = 10 or 3 years

When x = 10 years,

x -6 = 10 -6 = 4 years, so she is 4 years old six years ago.

When x = 3 years,

x -6 = 3 -6 = -3 years, cannot be. She cannot be -3 years old anytime.

Therefore, she is 10 years old at present. ------------answer.