only when and
when x = -2 or y = -2
when x = 3 or y = -2
y=-2 is the only one which makes both eqn 0, so y = -2 is the soln.
Thanks for your reply.
That makes sense but I'm wondering if there's an algebraic methodology I can use? I know that the other solution is x=0.5, so can I do the following:
Ignore (y+2) and (y+2) so you have
X + 2 + x - 3
= 2x -1
X = -0.5
This comes out, but doesn't seem like its the correct way to go about it!