Hi there,

Can anyone offer some advice on how one would go about solving this equation? I can't figure it out!

(x+2)(y+2)+(x-3)(y+2)=0

Thanks in advance,

Josh

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- Feb 20th 2013, 11:21 PMMarto1234Solve a pair of intersecting lines
Hi there,

Can anyone offer some advice on how one would go about solving this equation? I can't figure it out!

(x+2)(y+2)+(x-3)(y+2)=0

Thanks in advance,

Josh - Feb 20th 2013, 11:36 PMjakncokeRe: Solve a pair of intersecting lines
$\displaystyle (x+2)(y+2) + (x-3)(y+2) = 0 $ only when $\displaystyle (x+2)(y+2) = 0 $ and $\displaystyle (x-3)(y+2) = 0 $

$\displaystyle (x+2)(y+2) = 0 $ when x = -2 or y = -2

$\displaystyle (x-3)(y+2) = 0 $ when x = 3 or y = -2

y=-2 is the only one which makes both eqn 0, so y = -2 is the soln. - Feb 21st 2013, 12:27 AMMarto1234Re: Solve a pair of intersecting lines
Hi Dave,

Thanks for your reply.

That makes sense but I'm wondering if there's an algebraic methodology I can use? I know that the other solution is x=0.5, so can I do the following:

Ignore (y+2) and (y+2) so you have

X + 2 + x - 3

= 2x -1

X = -0.5

This comes out, but doesn't seem like its the correct way to go about it!