Thread: Rational Equations

(Note that most of your answers are algebraic expressions involving .)
A car starts on a trip and travels at a speed of 55 mph. Two hours later, a second car starts on the same trip and travels at a speed of 65 mph.
When the second car has been on the road for hours, the first car has traveled miles_________ and the second car has traveled miles________.
At time the distance between the first car and the second car is_________ miles.
The ratio of the distance the second car has traveled and the distance the first car has traveled is__________ .
The second car catches up with the first car___________ hours after the departure of the first car. (Those are some determined drivers!)
Hint: If you are having trouble with the last part of this problem reread the question carefully. It's not my wording, and if it's any consolation, I got hung up on it myself at first.


Please help I do not understand this problem and how to solve it

1 = 110 + 55t
2 = 65t
3 = 110 - 10t
4 = (22 + 11t)/13t
5 let 110 - 10t = 0, therefore answer is 11 hours

Thank you so much but the last two are incorrect

sorry i misread part 5, it is 13 hours
part 4 = 13t/22 + 11t it is broken down..its right

Thank you so much it is all correct now!