the first digit is 1,
since 3 times the number ends with 1 the original number should end with 7
also the number is divisible by 3.
so you have to check numbers such that : the f number starts with one, ends with seven and divisable by 3
I understand that I must learn math myself, but this exercise isn't as easy as I thought, so I need a help or any advices how to solve it.
So, we have to find the smallest natural [ ] number with these features:
1) The first digit is 1.
2) If we moved 1 to the end of the number, we would get a three times bigger/greater number.
the first digit is 1,
since 3 times the number ends with 1 the original number should end with 7
also the number is divisible by 3.
so you have to check numbers such that : the f number starts with one, ends with seven and divisable by 3
I know that number can be divisable by 3 if the sum of number's digits is divisable by 3. I tried to find an answer, but I think that I am doing wrong something. I think that number is really big :/ I checked some four-figure numbers, but all of them were wrong. Hmmm :/
Hello, Sott!
Find the smallest natural number with these features:
. . 1) The first digit is 1.
. . 2) If we moved 1 to the end of the number, we would get a three times greater number.
We have: .
We see that
We have: .
We see that
We have: .
We see that
We have: .
We see that
We have: .
We see that
We have: .
The smallest such number is