Hint: For (b) you are setting p=1850. When you have 1+0.12e^(0.2t), trying using natural log.
Additional Hint: e^(ln(x))=x
Its me again
The question I'm stuck on now is (this is gonna be diificult to type/understand)
Population of orchids is shown by (p is population and t is years from start)
p = 2800ae^(0.2t)/
1+ae(0.2t)
Given that population is 300 when study started (this means that time=0, right?)
a) prove that a=0.12, which I have done
b) use this to predict no of years before the population reaches 1850
does this mean that you make p=1850 and solve for t?
so,
1850 = 336e^(0.2t)/
1+0.12e^(0.2t)
I'm not too sure what to do from here?
c) show that,
p= 336/
0.12+e^(0.2t)
d) hence show that population cannot exceed 2800
I know its alot to ask for but I would be very grateful to anyone who would be kind enough to help me