Solving for x in an exponential equation

Hello, one question has proved insurmountable to me. Here it is:

(3/4)^x =(27/64)^(2x-3)

Here is what I have tried:

(3)^x/(4)^x=(27)^(2x-3)/(64)^(2x-3)

Then i cross multiplied to get...

(192)^(2x^2-3x)=(108)^(2x^2-3x)

I know that I need to make the bases the same, but i can't see how to do that at this point. Some guidance would be greatly appreciated.

Re: Solving for x in an exponential equation

Quote:

Originally Posted by

**takaj** Hello, one question has proved insurmountable to me. Here it is:

(3/4)^x =(27/64)^(2x-3)

Re: Solving for x in an exponential equation

Quote:

Originally Posted by

**Plato**

?

Re: Solving for x in an exponential equation

Quote:

Originally Posted by

**takaj** ?

The point is if then .

I showed how the bases are the same.

Re: Solving for x in an exponential equation