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Math Help - Solving the value

  1. #1
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    Solving the value

    If x^2 + y^2 = 1 then how do you find 2(x^4)+3(x^2*y^2)+(y^4)+(y*2)
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  2. #2
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    Re: Solving the value

    Replace y^2 with 1-x^2 and simplify.
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  3. #3
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    Re: Solving the value

    Hello, RuyHayabusa!

    \text{If }x^2 + y^2 \:=\:1,\,\text{ find: }\,2x^4+3x^2y^2+y^4+y^2

    \text{We have: }\:(2x^4 + 3x^2y^2 + y^4) + y^2 \;\;=\;\;(2x^2+y^2)\underbrace{(x^2+y^2)}_{ \text{This is 1}} + y^2

    . . . . . . . . =\;\;(2x^2+y^2)\!\cdot\!1 + y^2 \;\;=\;\;2x^2 + y^2 + y^2 \;\;=\;\;2x^2 + 2y^2


    . . . . . . . . =\;\;2\underbrace{(x^2+y^2)}_{\text{This is 1}} \;\;=\;\;2\!\cdot\!1 \;\;=\;\;2
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  4. #4
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    Re: Solving the value

    Thanks for your help both.
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