Unsure about linear programming

I have to solve this:

Minimize C = 30x + 10y subject to

1.8x + 0.9 >= 270|

0.3x + 0.2y >= 54

0.01x + 0.03y >= 3.9

x, y >= 0

The corner points I got for the feasible area are (60, 180), (120, 90) and (102, 96).

The minimum value I got is C = 3600 when x=60 and y=180, but an online programming calculator I used to check my answer tells me that the correct answer is C = 3000 when x=0 and y=300. O_o. Help?

Re: Unsure about linear programming

when x = 0, it does not even satisfy the first inequality

.9 $\displaystyle \geq 270 $ ?

Your solution seems correct to me.

Re: Unsure about linear programming

Thank you! :) *feels relieved* I checked my process of answering multiple times and didn't find anything wrong with it, so I was confused about how the answer could be wrong :) Maybe I didn't use the online programming calculator in the correct way :)

Re: Unsure about linear programming

Quote:

Originally Posted by

**Yoodle15** Thank you! :) *feels relieved* I checked my process of answering multiple times and didn't find anything wrong with it, so I was confused about how the answer could be wrong :) Maybe I didn't use the online programming calculator in the correct way :)

I expect you have a typo and that the first inequality is actually supposed to be $\displaystyle \displaystyle \begin{align*} 1.8x + 0.9y \geq 270 \end{align*}$.