• February 13th 2013, 11:03 AM
Yoodle15
I have to solve this:

Minimize C = 30x + 10y subject to
1.8x + 0.9 >= 270|
0.3x + 0.2y >= 54
0.01x + 0.03y >= 3.9
x, y >= 0

The corner points I got for the feasible area are (60, 180), (120, 90) and (102, 96).
The minimum value I got is C = 3600 when x=60 and y=180, but an online programming calculator I used to check my answer tells me that the correct answer is C = 3000 when x=0 and y=300. O_o. Help?
• February 13th 2013, 11:34 AM
jakncoke
when x = 0, it does not even satisfy the first inequality

.9 $\geq 270$ ?

Your solution seems correct to me.
• February 13th 2013, 12:02 PM
Yoodle15
I expect you have a typo and that the first inequality is actually supposed to be \displaystyle \begin{align*} 1.8x + 0.9y \geq 270 \end{align*}.