transfer all terms with y to the right side and all x to the left and solve for x ...to be a function of y..the interchange the x with y and thats it...you must find
(5x+1)/(2x-3) as inverse to the original function
Good luck
Minoas
So one problem is f(x)=x^3 , In my head I know its x^(1/3) because
y=x^3
Then i think I Do the third square root to both sides to get that answer but am not sure.
This is the one where Im haveing the most trouble
f(x)=(3x+1)/(2x-5) So I Multipy each side by 2x-5 and get
y(2x-5) which factors into
2xy-5y=3x+1 and am not sure what to do from here
Any help would be greatly appreciated.
The answer in the back of the book is y=(5x+1)/(2x-3)
even with that I cant figure out how they came up with it
transfer all terms with y to the right side and all x to the left and solve for x ...to be a function of y..the interchange the x with y and thats it...you must find
(5x+1)/(2x-3) as inverse to the original function
Good luck
Minoas
I can help you to a certain extent, but the ONLY thing I myself am unsure of is why it's 5x+1 and not 5x-1, or -5x+1 conversely.
First, the easiest way to solve this would be to switch the x's and y's. Equation becomes
.
You were correct to multiply the denominator, then you get
.
Distribute:
Isolate all terms with y on one side, so I'll subtract 3y from the right and 5x from the left to keep the formatting of your books answer more intact:
Factor out a y
and divide by 2x-3
Now you just have to hope that either your book is wrong or somebody can explain to you why it's 5x+1 without a negative.
Hope I helped at least a bit.
It started out as f(x)=(3x+1)/(2x-5) I think you did f(x)=(3x+1)/(2x+5)
Thank you though i just couldn't wrap my head around it.
I Was failing at getting like terms on their own side I think.
I went through it again and got the correct Answer TYVM
Also where is the reference material for this site to make my math problems look like yours
Oops, 2x-5 would indeed make a ton more sense as to why it's 5x+1 lol. Not sure why my mind read it as 2x+5.
And the way to format math problems like this is called LaTex, there's a specific sub-forum on this website with how to do it all. Everything goes inside [ tex][/tex] brackets.