the equations in question are log_{4}(x+1)-log_{4}3=1 and 4(7^{x})-7^{2x}=3

not sure what method to use to approach these.

thanks

age

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- Feb 10th 2013, 04:59 AMagehayoshinalogarithm equation help.
the equations in question are log

_{4}(x+1)-log_{4}3=1 and 4(7^{x})-7^{2x}=3

not sure what method to use to approach these.

thanks

age - Feb 10th 2013, 05:21 AMPlatoRe: logarithm equation help.
- Feb 10th 2013, 05:37 AMagehayoshinaRe: logarithm equation help.
Could you please explain how you got to those answers?

- Feb 10th 2013, 05:49 AMHallsofIvyRe: logarithm equation help.
In the first problem Plato used the fact that $\displaystyle log a- log b= log(a/b)$ and that $\displaystyle log_b(b)= 1$.

For the second, he substituted y for $\displaystyle 7^x$, as he said, and used the fact that $\displaystyle 7^{2x}= (7^x)^2= y^2$.