# Thread: Totally baffled

1. ## Totally baffled

I have an algebra problem where I need to find X, hopefully someone can help as I cannot see the wood for the trees on this one.

THanks for any help anyone

X - ((0.2*X) + (0.3*X)) = 100

2. "I cannot see the wood for the trees." Nice expression ^^

$\displaystyle X-((0.2X)+(0.3X))=100$

$\displaystyle \implies X(1-(0.2+0.3))=100$

$\displaystyle \implies X=\frac{100}{(1-(0.2+0.3))}$

$\displaystyle \implies X=\frac{100}{0.5}$

$\displaystyle \implies X=200$

3. Originally Posted by Sean12345
"I cannot see the wood for the trees." Nice expression ^^

$\displaystyle X-((0.2X)+(0.3X))=100$

$\displaystyle \implies X(1-(0.2+0.3))=100$

$\displaystyle \implies X=\frac{100}{(1-(0.2+0.3))}$

$\displaystyle \implies X=\frac{100}{0.5}$

$\displaystyle \implies X=200$
just in-regards to your answer, why did u remove the X's and place a 1 before the additions ?

4. Good point actually. I don't really know why i did that come to think of it. I'll just say i was giving an insight into how he would do harder questions of the same principal.