Hi,
It's been a long time since algebra so I just want to make sure I'm not making a stupid mistake on my homework. This is true, right?
sqrt(P*t)/sqrt(P) = sqrt(t)
Again, it may be simple, but thanks!
Hello, Coop!
This is true, right? . $\displaystyle \frac{\sqrt{P\!\cdot\!t}}{\sqrt{P}} \,=\, \sqrt{t}$
Yes, you are right!
Here are two ways . . .
$\displaystyle \frac{\sqrt{P\!\cdot\!t}}{\sqrt{P}} \:=\:\frac{{\color{red}\rlap{///}}\sqrt{P}\!\cdot\!\sqrt{t}}{{\color{red}\rlap{///}}\sqrt{P}} \:=\:\sqrt{t}$
$\displaystyle \frac{\sqrt{P\!\cdot\!t}}{\sqrt{P}} \:=\:\sqrt{\frac{{\color{red}\rlap{\,/}}P\!\cdot\!t}{{\color{red}\rlap{\,/}}P}} \:=\:\sqrt{t}$
It called LaTeX code
[tex]\frac{\sqrt{P\cdot t}}{\sqrt{P}}[/tex] gives $\displaystyle \frac{\sqrt{P\cdot t}}{\sqrt{P}}$.
Click on the “go advanced” tab. On the toolbar you will see $\displaystyle \boxed{\Sigma}$ clicking on that give the LaTeX wraps, [tex] [/tex]. The code goes between them.