Pretty sure factoring would be in the algebra department... hoping so. Anyways, can anyone help me factor this equation?
3x^2-10x+3
I can't seem to figure it out.
In such cases first multiply the coefficient of x^2 and constant term. In this case that is 3 *3 = 9. Find such factors of this product such that their sum equals the coefficient of x. In this question we get 9 = -1 * -9 and -1 + ( -9) = -10
Rewrite the quadratic by splitting the middle term.
3x^2 - x - 9x + 3 = x ( 3x - 1) - 3 ( 3x - 1 ) = (3x-1)(x-1) and there after it is quite simple.