I need help rationalizing the denominator if it is a cube root. I understand the if it is just a square root, you multiply it by itself. But im having trouble with rationalizing a cube root.

Here is the problem i need help with:

(3a)/(∛25a)

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- Feb 6th 2013, 03:59 PMHibby21Rationalizing the denominator that is a cube root?
I need help rationalizing the denominator if it is a cube root. I understand the if it is just a square root, you multiply it by itself. But im having trouble with rationalizing a cube root.

Here is the problem i need help with:

(3a)/(∛25a) - Feb 6th 2013, 04:29 PMPlatoRe: Rationalizing the denominator that is a cube root?
- Feb 6th 2013, 04:58 PMHallsofIvyRe: Rationalizing the denominator that is a cube root?
$\displaystyle \sqrt[3]{a}\sqrt[3]{a^2}= \sqrt[3]{a^3}= a$.

Or $\displaystyle \sqrt[3]{a}\left(\sqrt[3]{a}\right)^2= (\sqrt[3]{a})^3= a$.