Thread: (2p)^2013+(2q)^2013>2(pq)^2013

Proove that for real numbers p ang q ,

It's not true for all real numbers p and q. For example if p = 1/2 and q = -1 the left hand side is less than the right hand side for odd values of the exponent.

I suspect the problem should have been written "for positive real values of p and q..." In this case you can show that p = q/(q-1) and that p and q are both > 1. The equation boils down to , where 'n' is the exponent (2013 in this case).

Omg
This was on my examination and I don't pass because I could not proove.
Thank you very much.

Originally Posted by darence

Proove that for real numbers p ang q ,

like ebaines, I guess the real question was: prove that for positive reals p and q, ,


then, I think its pretty obvious because (now for the given relation to hold remember that p and q must be both positive and also greater than 1)


hence

It's OK, Thank you very much. But problem was as I wrote and I failed exam I will see what to do now...