Proove that for real numbers p ang q ,

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- February 6th 2013, 09:09 AMdarence(2p)^2013+(2q)^2013>2(pq)^2013
Proove that for real numbers p ang q ,

- February 6th 2013, 10:25 AMebainesRe: (2p)^2013+(2q)^2013>2(pq)^2013
It's not true for all real numbers p and q. For example if p = 1/2 and q = -1 the left hand side is less than the right hand side for odd values of the exponent.

I suspect the problem should have been written "for__positive__real values of p and q..." In this case you can show that p = q/(q-1) and that p and q are both > 1. The equation boils down to , where 'n' is the exponent (2013 in this case). - February 6th 2013, 11:08 AMdarenceRe: (2p)^2013+(2q)^2013>2(pq)^2013
Omg:(

This was on my examination and I don't pass because I could not proove.

Thank you very much. - February 6th 2013, 10:51 PMearthboyRe: (2p)^2013+(2q)^2013>2(pq)^2013
- February 7th 2013, 03:48 AMdarenceRe: (2p)^2013+(2q)^2013>2(pq)^2013
It's OK, Thank you very much. But problem was as I wrote and I failed exam :( I will see what to do now...