I need help with a riddle hoping someone can help
Mandy is 25 years older than Sandy
Sandy is 25 yrs younger than Mandy
Mandy's age is even
Sandy's age is odd
Together the sum of their ages is 63 how old is each sister?
anyone?
aren't these two statements redundant?
this isn't a riddle.Mandy's age is even
Sandy's age is odd
Together the sum of their ages is 63 how old is each sister?
anyone?
since Sandy's age is odd, we can write it as: $\displaystyle 2n + 1$ for $\displaystyle n \in \mathbb{N}$ ...(i used the natural numbers instead of the integers since negative ages make no sense, but whatever).
since Mandy is 25 yrs older than Sandy, Mandy's age is given by:
$\displaystyle 2n + 1 + 25 = 2n + 26$
The sum of their ages is 63, thus we have:
$\displaystyle 2n + 1 + 2n + 26 = 63$
now solve for $\displaystyle n$ and you will be able to find their ages
Hello, jak!
What a silly problem!
Where did it come from?
Mandy is 25 years older than Sandy.
Sandy is 25 yrs younger than Mandy. . . . . well, duh!
Mandy's age is even. . . . . Not relevant
Sandy's age is odd. . . . . . Who cares?
Together the sum of their ages is 63. . . . . Finally, something useful!
How old is each sister?
They're sisters? .Boy, that's really important!
(That's quite an age spread for siblings, isn't it?)
Let $\displaystyle S$ = Sandy's age.
Then $\displaystyle S + 25$ = Mandy's age.
"The sum of their ages is 63": . $\displaystyle S + (S + 25) \:=\:63$