1) Solve 7 to the power of x+1 divided by 49 to the power of y = 343, and 81 to the power of y times (1/27) to the power of x = 9 simultaneously.
2) Solve the equation 6 to the power of 2x-1 x 36 to the power of x = 1
I'm thinking that it might be helpful if you put brackets around certain parts in order to make the equation not ambiguous. Eg if a = 81, and b = y/27, and c = x, then you're looking at a^(b^c) = 9 ?
And if a = 7, b = x+1, c = 49, d = y, then are you looking at (a^b)/(c^d)? Or a^{(b/c)^d} etc ?
And also same with the other equation..... if a = 6, and b = 36*(2x-1), and c = x, then you're looking at a^(b^c) = 1 ?