Algebriacally, well Assume
Observe that (1)
so (i can do this since k/k = 1)
(im using (1) )
multiply the first equation by to get both denominaters equals
which equals
which is n+1 C k.
Algebriacally, well Assume
Observe that (1)
so (i can do this since k/k = 1)
(im using (1) )
multiply the first equation by to get both denominaters equals
which equals
which is n+1 C k.