Thread: Word Problem - Basic Math

Could someone please explain how to solve this? Thanks.

You need to find out how much is 80% of 10.

80% = 80/100 = 8/10 = 4/5.

so what is (4/5)(10/32)?

one you have that, say as a/b, you need to express this in 32nds.

if (by luck) there is a number c such that bc = 32, then a/b = ac/32. the "legal limit" of remaining tread is then (10 - ac)/32.

Which question are you referring to?
8/32 = 1/4.
Shouldn't the question be: how do you express 1/16 as 32nds, since 2/32 = 1/16?
2/32 is the answer to both questions btw.

Originally Posted by Deveno

80% = 80/100 = 8/10 = 4/5.

so what is (4/5)(10/32)?

one you have that, say as a/b, you need to express this in 32nds.

if (by luck) there is a number c such that bc = 32, then a/b = ac/32. the "legal limit" of remaining tread is then (10 - ac)/32.

Which question are you referring to?
8/32 = 1/4.
Shouldn't the question be: how do you express 1/16 as 32nds, since 2/32 = 1/16?
2/32 is the answer to both questions btw.

Originally Posted by Sprinkledozer

Which question are you referring to?
8/32 = 1/4.
Shouldn't the question be: how do you express 1/16 as 32nds, since 2/32 = 1/16?
2/32 is the answer to both questions btw.

80% of equals

This can be calculated:



Your question states: If 80% of the tread has worn off.

That means that we subtract 80% from the original number:

inches

As for the second part of your problem. It asks:

How much tread wear remains if the tread depth is ?

We now consider that the legal minimum for tread is
That means that we have to find the difference between the two:

inches of tread remaining.