There was a question that said: In an artithmetic sequence t(9) + t(22)= 61 what is the sum of the first 30 terms. Now i solved this question and i got an answer of 915. However I believe that I solved it a different way than my teacher because he said something about paring "things" to find the answer. If you know how to solve it that way please share it with me !

Either way, here is my solution:

$\displaystyle t(9) = 61 - t(22)$

Between t(9) and t(22) is 13 terms, so the sum of those terms would be:

$\displaystyle Sum13= 13/2(61-t(22) + t(22)= 396.5$

Now $\displaystyle t(9) +t(22) = 61$ is also the same as $\displaystyle t(31) = 61$

So, if t(31) = 61 , t(9) would then be = 61 - 22d and t(22) = 61 - 9d

Now sub those two new values for t9 and t22 and solve for the difference using the calculated sum 396.5!

$\displaystyle Sum13=13/2(61-22d+61-9d), 396.5= 6.5(122-31d), 61=122-31d, 61/31= d$

Now since d = 61/31 i can find the first term of the sequence. If t31= 61, t1=61-30d

So, t(1)= 61/31

Finally the sum of the 30 terms in this serires:

Sum30= 15(2(61/31)+(29)*61/31)

= 915