Hello folks Can anybody give me a step by step of why this statement is true? Code: (x^2 + 4x)/x = x + 4
(x^2 + 4x)/x = x + 4
Follow Math Help Forum on Facebook and Google+
Originally Posted by Assassinbeast Hello folks Can anybody give me a step by step of why this statement is true? Code: (x^2 + 4x)/x = x + 4 Step by step: $\displaystyle \frac {x^2 + 4x} x = \frac {x^2} x + \frac {4x}x = x ( \frac x x) + 4 ( \frac x x ) = x(1) + 4(1) = x + 4$ Note that $\displaystyle x \ne 0$, or else the fractions are undefined.
Originally Posted by ebaines Step by step: $\displaystyle \frac {x^2 + 4x} x = \frac {x^2} x + \frac {4x}x = x ( \frac x x) + 4 ( \frac x x ) = x(1) + 4(1) = x + 4$ Note that $\displaystyle x \ne 0$, or else the fractions are undefined. woooow, thank you so much man!! i wish it was written in my math book
Originally Posted by Assassinbeast Hello folks Can anybody give me a step by step of why this statement is true? Code: (x^2 + 4x)/x = x + 4 Or even easier... $\displaystyle \displaystyle \begin{align*} \frac{x^2 + 4x}{x} &= \frac{x \left( x + 4 \right)}{x} \\ &= x + 4 \end{align*}$ This is of course provided that $\displaystyle \displaystyle \begin{align*} x \neq 0 \end{align*}$.
Originally Posted by Prove It Or even easier... $\displaystyle \displaystyle \begin{align*} \frac{x^2 + 4x}{x} &= \frac{x \left( x + 4 \right)}{x} \\ &= x + 4 \end{align*}$ This is of course provided that $\displaystyle \displaystyle \begin{align*} x \neq 0 \end{align*}$. Thank you too man!! thats some cool tricks
View Tag Cloud