Why is this statement true?

Hello folks :)

Can anybody give me a step by step of why this statement is true?

Code:

`(x^2 + 4x)/x = x + 4`

Re: Why is this statement true?

Quote:

Originally Posted by

**Assassinbeast** Hello folks :)

Can anybody give me a step by step of why this statement is true?

Code:

`(x^2 + 4x)/x = x + 4`

Step by step:

$\displaystyle \frac {x^2 + 4x} x = \frac {x^2} x + \frac {4x}x = x ( \frac x x) + 4 ( \frac x x ) = x(1) + 4(1) = x + 4$

Note that $\displaystyle x \ne 0$, or else the fractions are undefined.

Re: Why is this statement true?

Quote:

Originally Posted by

**ebaines** Step by step:

$\displaystyle \frac {x^2 + 4x} x = \frac {x^2} x + \frac {4x}x = x ( \frac x x) + 4 ( \frac x x ) = x(1) + 4(1) = x + 4$

Note that $\displaystyle x \ne 0$, or else the fractions are undefined.

woooow, thank you so much man!! i wish it was written in my math book

Re: Why is this statement true?

Quote:

Originally Posted by

**Assassinbeast** Hello folks :)

Can anybody give me a step by step of why this statement is true?

Code:

`(x^2 + 4x)/x = x + 4`

Or even easier...

$\displaystyle \displaystyle \begin{align*} \frac{x^2 + 4x}{x} &= \frac{x \left( x + 4 \right)}{x} \\ &= x + 4 \end{align*}$

This is of course provided that $\displaystyle \displaystyle \begin{align*} x \neq 0 \end{align*}$.

Re: Why is this statement true?

Quote:

Originally Posted by

**Prove It** Or even easier...

$\displaystyle \displaystyle \begin{align*} \frac{x^2 + 4x}{x} &= \frac{x \left( x + 4 \right)}{x} \\ &= x + 4 \end{align*}$

This is of course provided that $\displaystyle \displaystyle \begin{align*} x \neq 0 \end{align*}$.

Thank you too man!! thats some cool tricks :D