Some guidance on this question

I have this question in the form

$\displaystyle 3y^2+[6y^2+(3y-4)]$

It just tells me to write this in its simplest form. So I have done

$\displaystyle 3y^2+[-6y^2-(-3y-4)]$

$\displaystyle 3y^2-6y^2+3y-4$

$\displaystyle -3y^2+3y-4$

Is this in its simplest form? I think I have turned it into a quadratic now right? So should I try to solve it using the quadratic formula?

Re: Some guidance on this question

What is $\displaystyle 3y^2- 6y^2$?

You cannot "solve" it because there is no equation to solve.

Re: Some guidance on this question

I didn't say solve. The question told me to put it in its simplest form. I'm asking if the form I have it in, is that the simplest it can be?

Re: Some guidance on this question

Quote:

Originally Posted by

**uperkurk** I didn't say solve. The question told me to put it in its simplest form. I'm asking if the form I have it in, is that the simplest it can be?

Are you now claiming that you did not post? Quote:

Originally Posted by

**uperkurk** I have this question in the form

$\displaystyle 3y^2+[6y^2+(3y-4)]$

So should I try to __solve__ it using the quadratic formula?

Re: Some guidance on this question

Quote:

Originally Posted by

**uperkurk** I have this question in the form

$\displaystyle 3y^2+[6y^2+(3y-4)]$

It just tells me to write this in its simplest form. So I have done

$\displaystyle 3y^2+[-6y^2-(-3y-4)]$

$\displaystyle 3y^2-6y^2+3y-4$

$\displaystyle -3y^2+3y-4$

Is this in its simplest form? I think I have turned it into a quadratic now right? So should I try to solve it using the quadratic formula?

Is there a typo in your first line of mathematics? In each successive line your 6y^2 is negated, but in the first line it is not...

Re: Some guidance on this question

Oh so I did, I meant to type simplify and it's ok I figured it out now, I used wolfram and it was in simplest form according to wolfram