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Math Help - simplifing exponent

  1. #1
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    simplifing exponent

    Thanks!!
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  2. #2
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    \frac{{4^n }}<br />
{{3^{n - 1} }} = \frac{4}<br />
{4} \cdot \frac{{4^n }}<br />
{{3^{n - 1} }} = 4 \cdot \frac{{4^{n - 1} }}<br />
{{3^{n - 1} }}

    The conclusion follows.
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  3. #3
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    Quote Originally Posted by Krizalid View Post
    \frac{{4^n }}<br />
{{3^{n - 1} }} = \frac{4}<br />
{4} \cdot \frac{{4^n }}<br />
{{3^{n - 1} }} = 4 \cdot \frac{{4^{n - 1} }}<br />
{{3^{n - 1} }}

    The conclusion follows.
    Thanks but I still have a couple of questions

    1) How did you know to pull out a 4 in step 2?
    2) How are you able to get n-1 in \\{{4^{n - 1} }} ?
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  4. #4
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    It's all based on the following properties:

    a^m:a^n=a^{m-n}

    &

    \frac{{a^k }}<br />
{{b^k }} = \left( {\frac{a}<br />
{b}} \right)^k

    By the way, this has nothing to do with "Calculus".
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  5. #5
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    Quote Originally Posted by Krizalid View Post

    By the way, this has nothing to do with "Calculus".
    Series
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  6. #6
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    Your question was special.

    In that case you should've posted the full question.
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