# Math Help - simplifing exponent

1. ## simplifing exponent

Thanks!!

2. $\frac{{4^n }}
{{3^{n - 1} }} = \frac{4}
{4} \cdot \frac{{4^n }}
{{3^{n - 1} }} = 4 \cdot \frac{{4^{n - 1} }}
{{3^{n - 1} }}$

The conclusion follows.

3. Originally Posted by Krizalid
$\frac{{4^n }}
{{3^{n - 1} }} = \frac{4}
{4} \cdot \frac{{4^n }}
{{3^{n - 1} }} = 4 \cdot \frac{{4^{n - 1} }}
{{3^{n - 1} }}$

The conclusion follows.
Thanks but I still have a couple of questions

1) How did you know to pull out a 4 in step 2?
2) How are you able to get n-1 in $\\{{4^{n - 1} }}$ ?

4. It's all based on the following properties:

$a^m:a^n=a^{m-n}$

&

$\frac{{a^k }}
{{b^k }} = \left( {\frac{a}
{b}} \right)^k$

By the way, this has nothing to do with "Calculus".

5. Originally Posted by Krizalid

By the way, this has nothing to do with "Calculus".
Series