# Need help solving this problem with fractions

• January 27th 2013, 04:03 PM
hossaim
Need help solving this problem with fractions
Can someone help me and give me a step by step to solve the following?

147/20/2-x = 147/10

So 147 over 20 over 2-x equals 147 over 10.
• January 27th 2013, 04:56 PM
topsquark
Re: Need help solving this problem with fractions
Quote:

Originally Posted by hossaim
Can someone help me and give me a step by step to solve the following?

147/20/2-x = 147/10

So 147 over 20 over 2-x equals 147 over 10.

Please correct me if I'm wrong. It sounds like your equation is
$\frac{147/20}{2 - x} = \frac{147}{10}$

If that's correct first note that you can cancel out the 147 from both sides. That leaves you with
$\frac{1}{20(2 - x)} = \frac{1}{10}$

Flip this equation upside down and solve for x

-Dan
• January 27th 2013, 09:11 PM
pspss
Re: Need help solving this problem with fractions
147/20/2-x = 147/10

147/20 ÷ (2-x) = 147/10
147/20 × 1/(2-x) = 147/10
147/20(2-x) = 147/10 divide by 147 to both sides
1/20(2-x) = 1/10
20(2-x) = 10 ---------- divide by 10
2(2-x) = 1
4 – 2x = 1
2x = 3
x = 3/2
-----
• January 28th 2013, 03:31 AM
topsquark
Re: Need help solving this problem with fractions
Quote:

Originally Posted by pspss
147/20/2-x = 147/10

147/20 ÷ (2-x) = 147/10
147/20 × 1/(2-x) = 147/10
147/20(2-x) = 147/10 divide by 147 to both sides
1/20(2-x) = 1/10
20(2-x) = 10 ---------- divide by 10
2(2-x) = 1
4 – 2x = 1
2x = 3
x = 3/2
-----

Is there an echo in here? (Hi)

-Dan