During cold weather, a car with a 20 Liter radiator containing 10% antifreeze must increase the solution to 25% antifreeze. How many liter of 10% antifreeze must be drained and replaced with 100% antifreeze?

Printable View

- January 27th 2013, 12:39 PMEspionageHelp with this Word Problem
During cold weather, a car with a 20 Liter radiator containing 10% antifreeze must increase the solution to 25% antifreeze. How many liter of 10% antifreeze must be drained and replaced with 100% antifreeze?

- January 27th 2013, 08:26 PMpspssRe: Help with this Word Problem
Let x L be removed so remaining is (20 – x)

and Let x L of 100% antifreez be relpaced.

(20 – x) × 10/100 + × x 100/100 = 20 × 25/100

2 – 0.1x + ×= 5

0.9x = 3

x = 3 1/3 L be replaced.

----