Can some one please verify my work? Thank you!
Tom throws a baseball so that the height of the ball is given by h(t)= -5t^2 + 20t + 1 where h is the height reached in meters and t is the time taken in seconds.
a) If the ball is caught at the same height it is thrown, how long was it in the air?
What i did:
set h(t) = 1 because that is the height when we through the ball, and solve.
1= -5t^2 +20t + 1
0= -5t^2 + 20t
0= -5t(t - 4)
There fore t = 4 & 0, and the ball was in the air for 4 seconds.
b) IF the ball is caught at the same height at which it is thrown, what is the maximum height reached by the ball?
What I did:
We have two symmetrical pairs ( 0,1) and (4,1).
So the AOS:
Sub x=2 in the equation to solve for max. height!
There fore the max height is 21.