I need to solve the following two equations for C. Any help/answers would be great. I'm quite rusty on my algebra at my age 0(zero)= (A*B*C) - [(D-E)*F*C*H)] X= (A*B*C) - [(D-E)*F*C*H)] Thank you!
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Originally Posted by ChemOsh I need to solve the following two equations for C. Any help/answers would be great. I'm quite rusty on my algebra at my age 0(zero)= (A*B*C) - [(D-E)*F*C*H)] X= (A*B*C) - [(D-E)*F*C*H)] Thank you! For the first one you can factor C from both terms. With 0 on the LHS that means we may assign any value to C. For the second one obviously C is still a factor of both terms, but now you can divide by the ugly term that's left on the RHS. -Dan
Thanks - confirmed my rusty math!
Topspuark answered it wrong, It is infact O-Fk-D-H-FE .E For the second one its obviously E
You are determined to be a jerk, aren't you?
0 = a - (D-E)b x = a - (D-E)b lnconsistent. Can't be solved.
Sorry, I misread the question. It's too late to edit it out. My apologies. -Dan PS I have no idea where Jordy got that equation from.
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