# Thread: Rearranging variable only equation

1. ## Rearranging variable only equation

I need to solve the following two equations for C. Any help/answers would be great. I'm quite rusty on my algebra at my age

0(zero)= (A*B*C) - [(D-E)*F*C*H)]

X= (A*B*C) - [(D-E)*F*C*H)]

Thank you!

2. ## Re: Rearranging variable only equation

Originally Posted by ChemOsh
I need to solve the following two equations for C. Any help/answers would be great. I'm quite rusty on my algebra at my age

0(zero)= (A*B*C) - [(D-E)*F*C*H)]

X= (A*B*C) - [(D-E)*F*C*H)]

Thank you!
For the first one you can factor C from both terms. With 0 on the LHS that means we may assign any value to C.
$0 = $AB - (D - E)FH$ \cdot C$

For the second one obviously C is still a factor of both terms, but now you can divide by the ugly term that's left on the RHS.

-Dan

3. ## Re: Rearranging variable only equation

Thanks - confirmed my rusty math!

4. ## Re: Rearranging variable only equation

Topspuark answered it wrong, It is infact O-Fk-D-H-FE .E

For the second one its obviously E

5. ## Re: Rearranging variable only equation

You are determined to be a jerk, aren't you?

6. ## Re: Rearranging variable only equation

0 = a - (D-E)b
x = a - (D-E)b

lnconsistent. Can't be solved.

7. ## Re: Rearranging variable only equation

Sorry, I misread the question. It's too late to edit it out. My apologies.

-Dan

PS I have no idea where Jordy got that equation from.