I need to solve the following two equations for C. Any help/answers would be great. I'm quite rusty on my algebra at my age (Worried)

0(zero)= (A*B*C) - [(D-E)*F*C*H)]

X= (A*B*C) - [(D-E)*F*C*H)]

Thank you!

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- Jan 25th 2013, 04:38 AMChemOshRearranging variable only equation
I need to solve the following two equations for C. Any help/answers would be great. I'm quite rusty on my algebra at my age (Worried)

0(zero)= (A*B*C) - [(D-E)*F*C*H)]

X= (A*B*C) - [(D-E)*F*C*H)]

Thank you! - Jan 25th 2013, 07:08 AMtopsquarkRe: Rearranging variable only equation
For the first one you can factor C from both terms. With 0 on the LHS that means we may assign any value to C.

$\displaystyle 0 = \[ AB - (D - E)FH \] \cdot C$

For the second one obviously C is still a factor of both terms, but now you can divide by the ugly term that's left on the RHS.

-Dan - Jan 25th 2013, 07:13 AMChemOshRe: Rearranging variable only equation
Thanks - confirmed my rusty math!

- Jan 25th 2013, 07:31 AMjordyrhodesRe: Rearranging variable only equation
Topspuark answered it wrong, It is infact O-Fk-D-H-FE .E

For the second one its obviously E - Jan 25th 2013, 10:12 AMHallsofIvyRe: Rearranging variable only equation
You are determined to be a jerk, aren't you?

- Jan 25th 2013, 12:10 PMHartlwRe: Rearranging variable only equation
0 = a - (D-E)b

x = a - (D-E)b

lnconsistent. Can't be solved. - Jan 25th 2013, 11:21 PMtopsquarkRe: Rearranging variable only equation
Sorry, I misread the question. It's too late to edit it out. My apologies.

-Dan

PS I have no idea where Jordy got that equation from.