Results 1 to 7 of 7

Math Help - Help, Urgent!

  1. #1
    Newbie
    Joined
    May 2005
    Posts
    7

    Help, Urgent! PLEASE HELP ME!!!

    I need help with the following problems:

    Siplify 1/3(3x) + [(-5x) + (5x)]


    Simplify and write with positive exponents
    xy^5
    _____
    x^3y

    Simplify
    √6x^2 * √30x

    Factor Completely
    324x^2 - 36y - 180x^2 + 20

    Factor Completely
    49x^2 + 28x + 4

    Solve and Check
    2[7x + 2 + 4(x + 1)] = -4x + 1

    Solve by factoring
    3x (x-4) = 5x^2 - 13x

    Solve by using the square root method
    (11x - 4)^2 = 12

    AND LASTLY

    SOLVE BY USING THE QUADRATIC FORMULA
    3x^2 = -12x - 2
    Last edited by hodap2001; May 9th 2005 at 12:23 PM.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Site Founder Math Help's Avatar
    Joined
    Apr 2005
    Posts
    171
    Simplify 1/3(3x) + [(-5x) + (5x)]

    1/3 * 3 = 1 so the first portion becomes x
    -5x + 5x = 0 so the second portion dissapears
    you are left with:

    x

    I'll do the second one aswell

    Simplify and write with positive exponents

    xy^5
    _____
    x^3y

    this can be wrtten as ..x ... y^5
    .............................----.*.----
    .............................x^3.....y

    The forst portion can ber written as 1/x^2 and the second potio as y^4/1
    multiply the two parts together and you get

    y^4
    ___
    x^2
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    May 2005
    Posts
    7

    Please NEED HELP WITH THE REMAINING

    Please Help Me With The Remaining Math Problems. These Are Due In Less Than Two Hours.
    Thanks!
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Site Founder Math Help's Avatar
    Joined
    Apr 2005
    Posts
    171
    Simplify
    √(6x^2) * √(30x)

    x√6 * √6 * √(5x)

    6x√(5x)
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Site Founder Math Help's Avatar
    Joined
    Apr 2005
    Posts
    171
    SOLVE BY USING THE QUADRATIC FORMULA
    3x^2 = -12x - 2

    3x^2 + 12x + 2 = 0

    a=3
    b=12
    c=2

    -12 +/- √(12^2 - 4*3*2)
    .............2*3

    -2 + (√120)/6
    -2 - (√120)/6

    which can be simplified to

    -2 + (√30)/3
    -2 - (√30)/3
    Attached Thumbnails Attached Thumbnails Help, Urgent!-quad.gif  
    Last edited by Math Help; May 9th 2005 at 01:08 PM.
    Follow Math Help Forum on Facebook and Google+

  6. #6
    Site Founder Math Help's Avatar
    Joined
    Apr 2005
    Posts
    171
    Solve and Check
    2[7x + 2 + 4(x + 1)] = -4x + 1

    14x + 4 + 8x +8 = -4x + 1
    22x + 12 = 1 - 4x

    26x = -11

    x = -11/26

    Check

    2[7(-11/26) + 2 + 4((-11/26) + 1)] = -4(-11/26) + 1
    22(-11/26) + 12 = 1 - 4(-11/26)

    both sides = 2.6923...
    Follow Math Help Forum on Facebook and Google+

  7. #7
    Newbie
    Joined
    May 2005
    Posts
    7

    Anyone know how to factor??

    There have been 65 people who viewed this, does anyone know how to factor those three problems. This forum has been the last resort because I couldn't figure them out on my own....
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Urgent!!!help with attempted questions - urgent
    Posted in the Statistics Forum
    Replies: 2
    Last Post: February 28th 2010, 12:29 AM
  2. I need urgent urgent hel with this parabola question
    Posted in the Pre-Calculus Forum
    Replies: 1
    Last Post: December 14th 2008, 04:48 PM
  3. Very urgent!
    Posted in the Algebra Forum
    Replies: 2
    Last Post: September 30th 2008, 01:01 PM
  4. Urgent HW help
    Posted in the Discrete Math Forum
    Replies: 2
    Last Post: March 14th 2008, 05:52 AM
  5. urgent HELP
    Posted in the Statistics Forum
    Replies: 1
    Last Post: July 12th 2007, 04:34 AM

Search Tags


/mathhelpforum @mathhelpforum