Originally Posted by

**hisajesh** In a 1000m race, if A gives B a 40 m start, A wins by 19 seconds, but if A gives B 30 seconds start, B wins by 40 m. Find the time each takes to run a 1000 m?

My attempt:

1. A gives B a 40 m start, A wins by 19 seconds: so B runs 960 m in x+19 seconds and A runs 1000 m in x seconds.

Speed A =960/x+19

Speed B=1000/x

2. A gives B 30 seconds start, B wins by 40 m: so B runs 1000 m in y-30 seconds and A runs 960 m in y seconds.

Speed A = 960/y

Speed B=1000/y-30

When I try to equaute, it does not work.

The book answer is A takes 125 seconds and B takes 150 seconds. Appreciate your help.