12x^6 + 7x^4 = 9315
Forgive my inadequacies, but could somebody show the steps I need to make x the subject?
I don't know how to do this when x doesn't have the same power index.
Any help appreciated. Thanks.
12x^6 + 7x^4 = 9315
Forgive my inadequacies, but could somebody show the steps I need to make x the subject?
I don't know how to do this when x doesn't have the same power index.
Any help appreciated. Thanks.
Hey TheDunce.
You will have to transform this into a cubic using the transformation u = x^2 to get 12u^3 + 7u^2 - 9315 = 0 and then use the cubic formula to solve for u first and then x using the relation between x and u.
Cubic function - Wikipedia, the free encyclopedia
Hello, TheDunce!
Does this mean that you have never ever solved a quadratic equation?$\displaystyle \text{Solve: }\:12x^6 + 7x^4 \:=\: 9315$
I don't know how to do this when x doesn't have the same power index. ??
Then who assigned you a sixth-degree equaton?
We have: .$\displaystyle 12x^6 + 7x^4 - 9315 \:=\:0$
We find that $\displaystyle x = \pm3$ are roots of the equation
. . and that: .$\displaystyle 12x^6 + 7x^4 - 9315 \;=\;(x^2-9)(12x^4 + 115x^2 + 1035)$
The quartic has no real roots.
Therefore, the only real roots are: .$\displaystyle x \:=\:+3,\,-3$
Thanks for the quick replies. I will study this. I'm trying to learn from a textbook and didn't know where to start on this one.
Soroban: I've solved some quadratic equations and used the quadratic formula so I guess the comment didn't make sense. Thanks for the help.