Thread: h such that the matrix is augmented...

Determine the value(s) of h such that the matrix is the augmented matrix of a consistent linear system?

1 h 2
5 20 8

Ok so I got 2h cannot = - 20
Then divide by 2 and got h cannot equal = -10?

Is this correct?

Originally Posted by Oldspice1212

Determine the value(s) of h such that the matrix is the augmented matrix of a consistent linear system?

1 h 2
5 20 8

Ok so I got 2h cannot = - 20
Then divide by 2 and got h cannot equal = -10?
Is this correct?

No it is not correct.

You need the matrix to be non-singular, determinate not zero.

I have to make it into a

1 0
0 1

Is that what you mean?

Originally Posted by Oldspice1212

I have to make it into a

1 0
0 1

Is that what you mean?

No you must have

Ooh haha I got -4, does it look correct now?

Originally Posted by Oldspice1212

Ooh haha I got -4, does it look correct now?

No that is not correct.
And I think that you are just guessing.
Read the question. If you understand the process, then the answer is easy.

Its 4 since (20-5h)x2=-2
So it's a augmented matrix of a consistant linear system if h cannot = 4?

Hello, Oldspice1212!

Determine the value(s) of h such that the matrix is the augmented matrix of a consistent linear system.

. .

The system is consistent if its determinant is not equal to zero.

If , we have: .

. . Hence: .

^ yup I got it, thanks guys