Determine the value(s) of h such that the matrix is the augmented matrix of a consistent linear system?
1 h 2
5 20 8
Ok so I got 2h cannot = - 20
Then divide by 2 and got h cannot equal = -10?
Is this correct?
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Determine the value(s) of h such that the matrix is the augmented matrix of a consistent linear system?
1 h 2
5 20 8
Ok so I got 2h cannot = - 20
Then divide by 2 and got h cannot equal = -10?
Is this correct?
Quote:
Originally Posted by Oldspice1212
No it is not correct.
You need the matrixto be non-singular, determinate not zero.
I have to make it into a
1 0
0 1
Is that what you mean?
Quote:
Originally Posted by Oldspice1212
No you must have
Ooh haha I got -4, does it look correct now?
No that is not correct.Quote:
Originally Posted by Oldspice1212
And I think that you are just guessing.
Read the question. If you understand the process, then the answer is easy.
Its 4 since (20-5h)x2=-2
So it's a augmented matrix of a consistant linear system if h cannot = 4? :D
Hello, Oldspice1212!
Quote:
Determine the value(s) of h such that the matrix is the augmented matrix of a consistent linear system.
. .![\left[\begin{array}{cc|c} 1&h&2 \\ 5&20&8 \end{array}\right]](http://latex.codecogs.com/png.latex?\left[\begin{array}{cc|c} 1&h&2 \\ 5&20&8 \end{array}\right])
The system is consistent if its determinant is not equal to zero.
If, we have: .
. . Hence: .
^ yup I got it, thanks guys :D