Having trouble with high school algebraic fractions

Hi,

I'm having a bit of trouble with the work I was assigned by my teacher. The problem goes:

1/(3-x) + (2x-5)/(x²-7x+12)

The common denominator is supposed to be (x-3)(x-4) and the answer is supposed to be x-1/cd. The problem is that two of the common denominator terms have the same variables but different signs, namely (3-x) and (x-3). I'm supposed to simplify out one of those factors and then switch the operator between the fractions so that this becomes a subtraction problem. The thing is I don't know which one of the factors to remove, which factor to multiply the numerator by, and how I should proceed in general. Can anyone help me?

Thanks!

Re: Having trouble with high school algebraic fractions

Quote:

Originally Posted by

**KevinShaughnessy** 1/(3-x) + (2x-5)/(x²-7x+12)

The common denominator is supposed to be (x-3)(x-4) and the answer is supposed to be x-1/cd.

Note that $\displaystyle \frac{1}{(3-x)}+\frac{2x-5}{x^2-7x+12}=\frac{2x-5}{(x-3)(x-4)}-\frac{1}{(x-3)}$.

Now can you see LCD?

Re: Having trouble with high school algebraic fractions

You need to know that 3- x= -(x- 3).

Re: Having trouble with high school algebraic fractions

Awesome, it makes sense now. Thanks guys, I really appreciate it!