Hey zsf1990.
Try using:
6 + 2x + 3x^3 - x^4 = - (x^4 - 3x^3 - 2x - 6)
Given 6 + 2x + 3x^{3} - x^{4}, how would I rearrange it into descending order to be factored? I know addition is commutative, but given that x^{4} is negative, how do I move that without changing the expression?
Thanks! Any chance you could explain how to factor 5x^{3} - 40? -40 isn't a perfect cube, so I'm feeling lost. This is what I get for missing a lecture I guess.
EDIT: Nevermind. Factor out a five to get x^{3} - 8, which is a difference of cubes. It's always the little things, lol.