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Math Help - trick question needs help ASAP !!

  1. #1
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    Question trick question needs help ASAP !!

    This is a ? my 5th-grader got (so I'm not smarter than a 5th grader!):
    "When dividing a 3-digit # by a 1-digit #, for what divisors can you get a remainder of 8? Explain." I'm totally baffled, except to take shots-in-the-dark on a thousand different combos! HELP, PLEASE!!!
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  2. #2
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    I think 9 would be the only possible because it is the only 1 digit number greater than 8. The remainder must be less than the divisor.
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  3. #3
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by SnipedYou View Post
    I think 9 would be the only possible because it is the only 1 digit number greater than 8. The remainder must be less than the divisor.
    indeed. you are correct

    you could also have listed all the forms for numbers divisible by 1 digit numbers which have a remainder 8 (there are only 9 or so), you would have found the divisor 9 to be the only appropriate choice. but that's too much work for a 5th grader i suppose
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  4. #4
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    Lightbulb Thanks for answer!

    How simple--easy to overlook the obvious sometimes !! I feel like a duphus. Thanks Again.
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  5. #5
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by StephE4kids View Post
    How simple--easy to overlook the obvious sometimes !! I feel like a duphus. Thanks Again.
    we all have those moments, don't beat yourself up. besides, you caught your mistake within a half hour, i have overlooked the obvious for hours sometimes. take care
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